Know who are you going to be like in your future!!!!

[Chimpas]

This and important numberologic test to know if your mind is related with someone important in the history of the world, it was done to many important characters and some of them picked the same numbers having almost the same personality, this is it:

1.Pick a number from 1 to 9
2.Multiply it for three
3.Plus 3
4.Multiply it for 3 again
You will obtain a number with 2 digits.
5.Sumate those numbers and see the result:

1=Albert Einstein
2=Sir Isaac Newton
3=Henry IV of France
4=LULA Da Silva
5=Francisco Villa
6=Fidel Castro
7=Barack Obama
8=Osama Bin Laden
9=Alex Ramon Barrios Sigala "Chimpas"
10=Adolph Hitler

[ING-X]

lol it picks 9 every time

[mysticremen11]

thats pro

[Jecko]

1.Pick a number from 1 to 9
2.Multiply it for three
3.Plus 3
4.Multiply it for 3 again
You will obtain a number with 2 digits.
5.Sumate those numbers and see the result:

I pick 4.7

4.7 x 3 = 14.1
14.1 + 3 = 17.1
17.1 x 3 = 51.3
lolwut

[Runnerguy2489]

It still works Jecko:

53.1 -> 5 + 3 + 1 = 9

[RingRush]

In other news this topic is lame.

[mzxrules]

And now, an attempt to prove that the given sequence will always give a result of 9...

1.Pick a number from 1 to 9
2.Multiply it for three
3.Plus 3
4.Multiply it for 3 again

Assume that the chosen number X is an integer between 1 and 9 inclusive. Going through the sequence step by step reveals an equation.

1. X
2. 3X
3. 3X+3 = 3(x+1)
4. 3*3(x+1) = 9(x+1)

As you can clearly see, regardless of what X is, the result at step 4 will always be divisible by 9. Since X is an integer between 1 and 9 inclusive, the result at step 4 must range between 18 and 90.

Now, there's a rule of divisibility for 9 where if the summation of the digits of a number is divisible by 9, then it too is also divisible by nine. Since the result at step 4 is a two digit number, the summation of it's digit cannot exceed 18 (9+9). What's more, no two single digit combination other than 9 and 9 sum to 18. Because 99 is outside of the range, but the result at step 4 is always divisible by nine, then the summation of the digits of the result from step 4 will always equal 9.

[AniMeowzerz]

And now, an attempt to prove that the given sequence will always give a result of 9...

<Insert some scientific shit here>

Goddamn, you scientists know the answer to everything, don't you

[aleckermit]

I find this thing to be much cooler: http://www.bored.com/mysticalball/

[Lexkeeta]

I choose e.

e*3 = 3e
+3 = 3(e+1)
*3 = 9(e+1)
9(e+1) ~ 33.46453645613140711824258724217396247981522384329963617470270864951668967318192835114243960672649784684719752738802...

[Elminster]

e is an irrational number.

Have fun checking your result...

[Lexkeeta]

that was the fucking point, lol

[Ragoul]

blah

[Chimpas]

I find this thing to be much cooler: http://www.bored.com/mysticalball/

Crap lol it works!!!

[AniMeowzerz]

I find this thing to be much cooler: http://www.bored.com/mysticalball/

System explained!
instructions are to take any number with 2 digits, add them, then subtract the sum from your original 2 digit number then it'll point to the symbol.
 10-19 always points to 9, 20-29 always points to 18, 30-39 always points to 27, 40-49 always points to 36, 50-59 always points to 45, 60-69 always points to 54, 70-79 always points to 63, 80-89 always points to 72, 90-99 always points to 81.
 all of the numbers that are being pointed back to are multiples of 9.
 take a look at the chart and the symbol next to each of the multiples of 9 are always going to be the same.